Take the 2-minute tour ×
Graphic Design Stack Exchange is a question and answer site for Graphic Design professionals, students, and enthusiasts. It's 100% free, no registration required.

How do I find out the exact size of a graphic or image after it has a clipping mask applied in Illustrator? When you just select the image or do Ctrl+A it shows the entire image size(including the masked unwanted portion) in the transform palette and I just need the final dimensions of the image. Can anyone suggest how I can find out what the masked image size is?

share|improve this question
See also graphicdesign.stackexchange.com/questions/21513/…. Maybe that helps. –  Vincent Nov 5 '13 at 15:07
You should post what version of Illustrator you are using, because more recent versions don't show the clipped content. –  Scott Nov 5 '13 at 16:17
Sorry, I am using Adobe Illustrator CS4. –  Logesh Nov 5 '13 at 16:34

1 Answer 1

If you are using an older version of Illustrator, you'll need to not simply "Select All", or select all, then de-select the masked content and use the Direct Selection Tool (White arrow) - or Layers Panel - to select only the clipping mask shape rather than the entire clipped group.

The inclusion of non-visible clipped content was an annoyance many users complained about, which is why more recent versions of Illustrator no longer show content which is not visible.

share|improve this answer
Thanks Scott, I can understand using the Direct Selection Tool to find size of the masked content. But I get graphics, advertisements in vector and there will be multiple of empty boxes or color outlines in addition to the masked content and it will have more number of paths too.. If I am able to find out only the final masked size that will be great. –  Logesh Nov 5 '13 at 19:26
There's no way, in previous versions, to simply disable the display of non-visible clipped content. You can draw a rectangle around the area you wish to measure and measure the rectangle. That's about your best bet. –  Scott Nov 6 '13 at 3:45

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.