Graphic Design Stack Exchange is a question and answer site for Graphic Design professionals, students, and enthusiasts. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I am using Illustrator to apply a custom pattern brush on the path of a circle to create and image like so:

enter image description here

But I can't get my shape to repeat across the circle line properly and overlap itself, I end up with something like this:

enter image description here

I can get the overlap to work if I use a Scatter Brush but then I don't get the rotation like the Pattern Brush:

enter image description here

What is the best way to achieve my result?

share|improve this question
find the Rotation relative to field in the Scatter Brush Option dialog, and change it to Path instead of 'Page'. – Vincent Jun 20 '14 at 15:14
up vote 4 down vote accepted

There's a second problem with pattern brushes here - even if you got around the overlapping problem, the straight lines would become distorted (curved).

Try Effects > Distort & Transform > Transform. Copies, moves, rotates, with overlaps, without distortion:

enter image description here

For a circle, make sure Copies x Angle = 360

share|improve this answer
Perfect! thankyou :) – SaturnsEye Jun 20 '14 at 15:16

Pattern brushes are dependent upon their tile. If the tile artwork does not overlap itself, then the brush isn't going to either. You can't force pattern brush tiles to overlap themselves within the brush.

A blend would probably be a better solution for what you are after:

enter image description here

Or an effect....

enter image description here

share|improve this answer
Is there a way of doing this plus rotating around the circle? like my example image? – SaturnsEye Jun 20 '14 at 15:05
see updated answer – Scott Jun 20 '14 at 15:14

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.