Take the 2-minute tour ×
Graphic Design Stack Exchange is a question and answer site for professional graphic designers and non-designers trying to do their own graphic design. It's 100% free, no registration required.

I made a circle, and above that I put a compound path which I download from internet, a custom B, I want to just take the circle without the custom B, I did it before, let say a circle with star above, if I want to take the circle without star I will use path finder, but it seems not working for compound path any solution?

http://s7.postimage.org/dm28jozvv/bcoin.png

share|improve this question
    
erm....... huh? –  Scott Sep 7 '12 at 18:34
    
see here, I want to have the circle without the B. Cannot use pathfinder remove front, it won't work –  Umair Ibrahim Sep 7 '12 at 19:16
    
    
You need to check the objects then. There's no reason Pathfinder > Minus Front (Subtract From Shape Area in CS3) shouldn't work. Make certain your "internet" image doesn't have a clipping mask applied to it or some other construction complexity it doesn't need. –  Scott Sep 7 '12 at 20:35
    
it didn't work, maybe because it's a compound path, making from many path. I solved them by divide object. –  Umair Ibrahim Sep 7 '12 at 20:40
show 2 more comments

closed as not a real question by JohnB Jun 2 '13 at 14:55

It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question.

1 Answer

Objects of the same group won't behave normal using the pathfinder. Having a compound for the B would suffice. I think you don't need to have it in a group or in a group together with the background, respectively other elements.

share|improve this answer
add comment

Not the answer you're looking for? Browse other questions tagged or ask your own question.