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Jul 20, 2015 at 17:48 vote accept JWhiteUX
Jul 20, 2015 at 7:34 history edited JWhiteUX CC BY-SA 3.0
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Jul 20, 2015 at 7:24 comment added JWhiteUX okie dokie. I've been doing that in Illustrator. Thanks for your help @DA01
Jul 20, 2015 at 7:22 comment added DA01 "So if the menu bar is 56dp tall, and I'm designing @2x, make it 112px tall" = yes! You got i!
Jul 20, 2015 at 7:22 answer added KMSTR timeline score: 1
Jul 20, 2015 at 7:22 comment added DA01 DP = Density-independent Pixels. You really don't have to worry about what it is--merely what it represents. On a 3x density screen, 1dp = 3 screen pixels. On a 2x screen, 2 screen pixels, etc.
Jul 20, 2015 at 7:22 comment added JWhiteUX So if the menu bar is 56dp tall, and I'm designing @2x, make it 112px tall?
Jul 20, 2015 at 7:19 comment added JWhiteUX What I'm constantly struggling with (which is why I like vector design tools over raster) is DP. DP doesn't translate well. At the moment I'm designing 1920x1200 (N7 screen) @320DPI
Jul 20, 2015 at 7:18 comment added DA01 Ignore DPI. If you have a 340px wide screen you are designing for, make your image 340px wide. If said screens support 2x, then make it 680px wide.
Jul 20, 2015 at 7:17 comment added JWhiteUX See thats what I don't get. I understand the screen dimensions, but when the menu bar is supposed to be 56dp tall, 56dp in a 300DPI document is going to be very small, say compared to a 72dpi document.
Jul 20, 2015 at 7:15 comment added DA01 in terms of the image, DPI is irrelevant. Pixel dimension is the key. As for Android devices, it's a pretty varied landscape and, frustratingly, come in many different shapes and sizes.
Jul 20, 2015 at 7:12 history asked JWhiteUX CC BY-SA 3.0