5

Is there any way to create this kind of random mesh in Adobe Illustrator besides doing that manually? Not interested in these bold dots, just the mesh.enter image description here

2
6

Quickly adapted form this answer. Be sure to have round joints and non filled as your color setting or you get random stuff:

#target illustrator

var delunlay = getDelunlay();
var points = []

//~ var sel =  activeDocument.selection;
//~ for(var i=0; i < sel.length; i++){
//~     points.push(sel[i].position);
//~ }

for (var i = 0;i <40;i++){
    points.push([getRandomInt(100,400),getRandomInt(-200,-50)]);
}

var tris = delunlay.triangulate(points);


for(var i = 0; i < tris.length;i+=3 ){
    var obj = activeDocument.pathItems.add();
    obj.setEntirePath([points[tris[i]], points[tris[i+1]],points[tris[i+2]]]);
    obj.closed = true;
}


function getRandomInt(min, max) {
  min = Math.ceil(min);
  max = Math.floor(max);
  return Math.floor(Math.random() * (max - min)) + min; //The maximum is exclusive and the minimum is inclusive
}

// https://github.com/ironwallaby/delaunay/blob/master/delaunay.js
// slightly modified to work here 
function getDelunlay() {
  "use strict";

  var EPSILON = 1.0 / 1048576.0;

  function supertriangle(vertices) {
    var xmin = Number.POSITIVE_INFINITY,
        ymin = Number.POSITIVE_INFINITY,
        xmax = Number.NEGATIVE_INFINITY,
        ymax = Number.NEGATIVE_INFINITY,
        i, dx, dy, dmax, xmid, ymid;

    for(i = vertices.length; i--; ) {
      if(vertices[i][0] < xmin) xmin = vertices[i][0];
      if(vertices[i][0] > xmax) xmax = vertices[i][0];
      if(vertices[i][1] < ymin) ymin = vertices[i][1];
      if(vertices[i][1] > ymax) ymax = vertices[i][1];
    }

    dx = xmax - xmin;
    dy = ymax - ymin;
    dmax = Math.max(dx, dy);
    xmid = xmin + dx * 0.5;
    ymid = ymin + dy * 0.5;

    return [
      [xmid - 20 * dmax, ymid -      dmax],
      [xmid            , ymid + 20 * dmax],
      [xmid + 20 * dmax, ymid -      dmax]
    ];
  }

  function circumcircle(vertices, i, j, k) {
    var x1 = vertices[i][0],
        y1 = vertices[i][1],
        x2 = vertices[j][0],
        y2 = vertices[j][1],
        x3 = vertices[k][0],
        y3 = vertices[k][1],
        fabsy1y2 = Math.abs(y1 - y2),
        fabsy2y3 = Math.abs(y2 - y3),
        xc, yc, m1, m2, mx1, mx2, my1, my2, dx, dy;

    /* Check for coincident points */
    if(fabsy1y2 < EPSILON && fabsy2y3 < EPSILON)
      throw new Error("Eek! Coincident points!");

    if(fabsy1y2 < EPSILON) {
      m2  = -((x3 - x2) / (y3 - y2));
      mx2 = (x2 + x3) / 2.0;
      my2 = (y2 + y3) / 2.0;
      xc  = (x2 + x1) / 2.0;
      yc  = m2 * (xc - mx2) + my2;
    }

    else if(fabsy2y3 < EPSILON) {
      m1  = -((x2 - x1) / (y2 - y1));
      mx1 = (x1 + x2) / 2.0;
      my1 = (y1 + y2) / 2.0;
      xc  = (x3 + x2) / 2.0;
      yc  = m1 * (xc - mx1) + my1;
    }

    else {
      m1  = -((x2 - x1) / (y2 - y1));
      m2  = -((x3 - x2) / (y3 - y2));
      mx1 = (x1 + x2) / 2.0;
      mx2 = (x2 + x3) / 2.0;
      my1 = (y1 + y2) / 2.0;
      my2 = (y2 + y3) / 2.0;
      xc  = (m1 * mx1 - m2 * mx2 + my2 - my1) / (m1 - m2);
      yc  = (fabsy1y2 > fabsy2y3) ?
        m1 * (xc - mx1) + my1 :
        m2 * (xc - mx2) + my2;
    }

    dx = x2 - xc;
    dy = y2 - yc;
    return {i: i, j: j, k: k, x: xc, y: yc, r: dx * dx + dy * dy};
  }

  function dedup(edges) {
    var i, j, a, b, m, n;

    for(j = edges.length; j; ) {
      b = edges[--j];
      a = edges[--j];

      for(i = j; i; ) {
        n = edges[--i];
        m = edges[--i];

        if((a === m && b === n) || (a === n && b === m)) {
          edges.splice(j, 2);
          edges.splice(i, 2);
          break;
        }
      }
    }
  }

  var Delaunay = {
    triangulate: function(vertices, key) {
      var n = vertices.length,
          i, j, indices, st, open, closed, edges, dx, dy, a, b, c;

      /* Bail if there aren't enough vertices to form any triangles. */
      if(n < 3)
        return [];

      /* Slice out the actual vertices from the passed objects. (Duplicate the
       * array even if we don't, though, since we need to make a supertriangle
       * later on!) */
      vertices = vertices.slice(0);

      if(key)
        for(i = n; i--; )
          vertices[i] = vertices[i][key];

      /* Make an array of indices into the vertex array, sorted by the
       * vertices' x-position. Force stable sorting by comparing indices if
       * the x-positions are equal. */
      indices = new Array(n);

      for(i = n; i--; )
        indices[i] = i;

      indices.sort(function(i, j) {
        var diff = vertices[j][0] - vertices[i][0];
        return diff !== 0 ? diff : i - j;
      });

      /* Next, find the vertices of the supertriangle (which contains all other
       * triangles), and append them onto the end of a (copy of) the vertex
       * array. */
      st = supertriangle(vertices);
      vertices.push(st[0], st[1], st[2]);

      /* Initialize the open list (containing the supertriangle and nothing
       * else) and the closed list (which is empty since we havn't processed
       * any triangles yet). */
      open   = [circumcircle(vertices, n + 0, n + 1, n + 2)];
      closed = [];
      edges  = [];

      /* Incrementally add each vertex to the mesh. */
      for(i = indices.length; i--; edges.length = 0) {
        c = indices[i];

        /* For each open triangle, check to see if the current point is
         * inside it's circumcircle. If it is, remove the triangle and add
         * it's edges to an edge list. */
        for(j = open.length; j--; ) {
          /* If this point is to the right of this triangle's circumcircle,
           * then this triangle should never get checked again. Remove it
           * from the open list, add it to the closed list, and skip. */
          dx = vertices[c][0] - open[j].x;
          if(dx > 0.0 && dx * dx > open[j].r) {
            closed.push(open[j]);
            open.splice(j, 1);
            continue;
          }

          /* If we're outside the circumcircle, skip this triangle. */
          dy = vertices[c][1] - open[j].y;
          if(dx * dx + dy * dy - open[j].r > EPSILON)
            continue;

          /* Remove the triangle and add it's edges to the edge list. */
          edges.push(
            open[j].i, open[j].j,
            open[j].j, open[j].k,
            open[j].k, open[j].i
          );
          open.splice(j, 1);
        }

        /* Remove any doubled edges. */
        dedup(edges);

        /* Add a new triangle for each edge. */
        for(j = edges.length; j; ) {
          b = edges[--j];
          a = edges[--j];
          open.push(circumcircle(vertices, a, b, c));
        }
      }

      /* Copy any remaining open triangles to the closed list, and then
       * remove any triangles that share a vertex with the supertriangle,
       * building a list of triplets that represent triangles. */
      for(i = open.length; i--; )
        closed.push(open[i]);
      open.length = 0;

      for(i = closed.length; i--; )
        if(closed[i].i < n && closed[i].j < n && closed[i].k < n)
          open.push(closed[i].i, closed[i].j, closed[i].k);

      /* Yay, we're done! */
      return open;
    },
    contains: function(tri, p) {
      /* Bounding box test first, for quick rejections. */
      if((p[0] < tri[0][0] && p[0] < tri[1][0] && p[0] < tri[2][0]) ||
         (p[0] > tri[0][0] && p[0] > tri[1][0] && p[0] > tri[2][0]) ||
         (p[1] < tri[0][1] && p[1] < tri[1][1] && p[1] < tri[2][1]) ||
         (p[1] > tri[0][1] && p[1] > tri[1][1] && p[1] > tri[2][1]))
        return null;

      var a = tri[1][0] - tri[0][0],
          b = tri[2][0] - tri[0][0],
          c = tri[1][1] - tri[0][1],
          d = tri[2][1] - tri[0][1],
          i = a * d - b * c;

      /* Degenerate tri. */
      if(i === 0.0)
        return null;

      var u = (d * (p[0] - tri[0][0]) - b * (p[1] - tri[0][1])) / i,
          v = (a * (p[1] - tri[0][1]) - c * (p[0] - tri[0][0])) / i;

      /* If we're outside the tri, fail. */
      if(u < 0.0 || v < 0.0 || (u + v) > 1.0)
        return null;

      return [u, v];
    }
  };
  return Delaunay;
}

Running this results in different image each time but heres an example:

enter image description here

You could use some more structured random starting point if you wish this is just fast to do. And hey you asked for random.

2
  • how do you apply such a script to an image in illustrator?
    – Webster
    Nov 1 '17 at 22:08
  • @Webster you paste the code into a plain text file. Then name it xxyyzz.jsx. Then either: 1. copy the file into your scripts folder and execute from scripts menu. 2. drag and drop file on illustrator. 3. open file in extendscript toolkit and hit play.
    – joojaa
    Nov 2 '17 at 5:09

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