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i am looking for GREP help. I have an issue where i need to delete every line that contains [DELETELINE].

So that

[DELETELINE] 
TestText
Test [DELETELINE] loremipsum
Example
[DELETELINE] loremipsum
loremipsum [DELETELINE]
[DELETELINE]

becomes

TestText
Example

I only can get parts of it to work. Like delete the line if [DELETELINE] is in the middle or in the beginning or at the end. But i need an expression that catches all cases.

Is that possible?

EDIT:

What i got is this:

^.+\[DELETELINE\].+\r

But this selects only the third line.

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1 Answer 1

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I think i found the answer

the following grep works for all cases

^.*\[DELETELINE\].*(\r?|\n?)

^ is beginning of a paragraph \r and \n are different types of linebreaks so everything should be catched.

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    With this query, if your last line must be deleted, it wouldn't be caught because there would be no vertical space at the end of it. Try .*[DELETELINE].*\v? in order to catch it as well. FYI \v means vertical space (it catches both \r and \n) and ? means zero or one time
    – Vinny
    Jan 8, 2018 at 8:39
  • Your recommendation targets every line. Also those two i don't want to touch. But the ? was a good hint. With that my solution works. + 1
    – Pat_Morita
    Jan 8, 2018 at 9:35
  • Oh I see... the anti-slashes before the brackets were deleted in my comment. Just type them back ^^
    – Vinny
    Jan 8, 2018 at 9:50

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