1

I have two circles. One small blue circle and one big pink circle.

Blue circle intersects the pink circle like the image enter image description here

I want remove just the part of blue ball which is outside of pink ball. I tried to select both two balls and do difference but it also removes the part of blue ball which is inside of pink ball

  • What have you tried? Do you know about Boolean operations in Inkscape? – Billy Kerr Jul 3 '18 at 15:38
  • @BillyKerr No. I watched some online youtube tutorials and they didnt do anything with boolean. – javaprogrammer Jul 3 '18 at 20:05
  • That's strange, because these boolean operations are like the basics of vector image editing software such as Inkscape. The answer given by @Pinback explains how to do it using one of the boolean operations (Exclusion). – Billy Kerr Jul 3 '18 at 21:45
2

Make sure they are both path objects -

Path -> Object to Path

Duplicate the red circle, select the two circles you want to work on then use the pathing tools

Path -> Exclusion, Path -> Break Apart

discard the lower circle remnant.

  • 1
    'Path > Object to Path' is not needed (anymore?), Inkscape will convert the circles automatically. – Moini Jul 5 '18 at 13:11
  • it depends - 0.92 is still the latest for some platforms which doesn't do this and will not behave as expected as a result – Pinback Jul 5 '18 at 13:18
  • 0.92.3 does, and 0.92.2, too, as well as 0.91... (these are the ones I have installed) – Moini Jul 5 '18 at 13:19
  • 1
    Not on 0.92.2 OSX it doesn't which is what I used - no path effects will work on circle or rectangles unless you convert them. However good to know that at some point in the future the behaviour will be more intuitive. – Pinback Jul 5 '18 at 13:32
  • This is not a path effect, but a Boolean operation. Can you test again, please? And make a bug report if that is true? – Moini Jul 11 '18 at 12:32

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.