2

In the drawing you see five paths (orange pink green blue and red), which define the boundaries of 4 regions (a b c and d). I now want to create those regions so they are fillable, and without crazy "op-art" effects due to differing directions. For instance, to create region b, I need to use the pink path (which is shared with c), the green path (shared with a) and part of the blue path (shared with d).

What is a process for doing this that is efficient? My actual drawing has dozens of regions and I'd like a process that doesn't take a week.paths before making into regions

  • 1
    If each shared border was one single path, with no gaps obviously, then it would be possible to use the technique described in the question I answered here. But you would have to cut up some of the paths at the interesctions in your design first before doing that. – Billy Kerr Dec 22 '18 at 8:08
  • 1
    Here's a proof of concept showing how the technique in the other answer works, on a similar design problem. – Billy Kerr Dec 22 '18 at 8:40
  • 1
    Works perfectly! Thank you.... feel free to do it as an actual answer and I'll accept. You saved me a ton of time. – rob Dec 22 '18 at 8:52
  • OK I will add it as an answer now. – Billy Kerr Dec 22 '18 at 8:53
  • 1
    karmatics.com/stuff/stackexchange.svg – rob Dec 22 '18 at 8:58
2

If each shared border was one single path, with no gaps obviously, then it would be possible to use the technique described in the question I answered here. So, to do that, you would have to cut up some of the paths at the intersctions in your design first before doing that.

Here's a proof of concept showing how the technique in the other answer works on a similar design problem

enter image description here

Your Answer

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Not the answer you're looking for? Browse other questions tagged or ask your own question.