2

How I can add an anchor point for each intersected selected paths in illustrator automatically?

I know smart Guide and add anchor point tool can do the job but it will add just one anchor in the front path only. If I use pathfinder outline or the scissors my paths get cut and I have to re-join them again one by one.

enter image description here

  • trim fuction is available in hotdoor cadtools – joojaa Nov 8 '14 at 8:35
  • Update: shapebuilder does this of you still need this – joojaa May 6 '15 at 4:32
1

As you noticed, the Add Anchor Point tool only adds a single point to the front-most path. After adding it to the front path though, you can select the other path, and then while it is selected, use the Add Anchor Point tool again. Since the back path is selected, it will be the destination of the new anchor point.

Add Anchor Point

I know it isn't automated, but at least you don't have to re-join paths after.

1

I've noticed that in fact the Shape Builder has this side effect that does what you ask. When you select curves for shape building, Adobe temporarily intersects all curves that participate in the deletion. Once you commit a shape build, this 'temporary' becomes in fact fixed.

How to use? Continue the curve you want to do this; draw a line to block the effect. Alt shape build drag so the continuation and blocker get deleted, this will cause all intersections to appear on the curves.

This is a bit of a hack, but it saved me form some angst last week.

0

There is no automated method I'm aware of to auto-add anchors at path intersections.

Pathfinder > Trim may offer an acceptable result is your paths are part of shapes (close paths) and not merely open paths.

  • yes it may be a solution for close paths but actually I am asking bout open paths. sorry I wasn't clear enough. – hsawires Nov 6 '14 at 14:28
  • There's nothing stopping you from closing a path, using Pathfinder,then removing the portions of the closed path you don't want. – Scott Nov 6 '14 at 14:28
  • sure, I am using this method in simple and easy shapes. but this method will be impossible with complex illustrations. – hsawires Nov 6 '14 at 14:34

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.